python: expose language_by_filename()

Signed-off-by: Alexander Bezzubov <bzz@apache.org>

python/enry.py

@@ -26,15 +26,29 @@ def language_by_extension(filename: str) -> str:
     return lang
 
 
+def language_by_filename(filename: str) -> str:
+    fName = py_str_to_go(filename)
+    guess = lib.GetLanguageByFilename(fName)
+    lang = go_str_to_py(guess.r0)
+    return lang
+
+
 ## Test
 
 
 def main():
-    files = ["Parse.hs", "some.cpp", "and.go", "type.h"]
+    files = ["Parse.hs", "some.cpp", "and.go", "type.h", ".bashrc"]
+
+    print("strategy: extension")
     for filename in files:
         lang = language_by_extension(filename)
         print("file: {:10s} language: '{}'".format(filename, lang))
 
+    print("\nstrategy: filename")
+    for filename in files:
+        lang = language_by_filename(filename)
+        print("file: {:10s} language: '{}'".format(filename, lang))
+
 
 if __name__ == "__main__":
     main()

python/enry_build.py

@@ -15,6 +15,14 @@ struct GetLanguageByExtension_return {
 };
 
 extern struct GetLanguageByExtension_return GetLanguageByExtension(GoString p0);
+
+/* Return type for GetLanguageByFilename */
+struct GetLanguageByFilename_return {
+	GoString r0; /* language */
+	GoUint8 r1; /* safe */
+};
+
+extern struct GetLanguageByFilename_return GetLanguageByFilename(GoString p0);
 """)
 
 # set_source() gives the name of the python extension module to